2x^2-760x+19712=0

Solution for 2x^2-760x+19712=0 equation:

2x^2-760x+19712=0

a = 2; b = -760; c = +19712;
Δ = b2-4ac
Δ = -7602-4·2·19712
Δ = 419904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{419904}=648$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-760)-648}{2*2}=\frac{112}{4}
=28
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-760)+648}{2*2}=\frac{1408}{4}
=352
$